test

by

$\Delta \vec{p} = \vec{p}_2 – \vec{p}_1 = (-\vec{p}) – \vec{p} = -2\vec{p}$

$\text{Magnitude of change } |\Delta \vec{p}| = 2p$

2. Change in Velocity in Circular Motion

Let a particle move along a circular path of constant radius with a uniform speed v. We want to find the change in its velocity when it completes exactly half a revolution.

Velocity at the starting point: v→1=v→\vec{v}_1 = \vec{v}

Velocity at the half-way point: vβ†’2=βˆ’vβ†’\vec{v}_2 = -\vec{v} (direction completely reverses)

The change in velocity (Δv→\Delta \vec{v}) is :

$\Delta \vec{v} = \vec{v}_2 – \vec{v}_1 = (-\vec{v}) – \vec{v} = -2\vec{v}$

Magnitude of change |Ξ”vβ†’|=2v\text{Magnitude of change } |\Delta \vec{v}| = 2v